"RMudkips" (rmudkips) 01/21/2014 at 09:00 • Filed to: ghostride the blip

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Any have some good trigonometric identity questions? (e.g sin x/cos x = tan x, sin^2 x + cos^2 x = 1). Studying for afternoon's exam.

themanwithsauce - has as many vehicles as job titles > RMudkips 01/21/2014 at 09:17

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Two drifters head into a turn consecutively. Bill is in a supra who enters turns with a slide angle of 45 degrees. Ted is in an RX-7 who enters turns with a slide angle of 40 degrees. If Bill and Ted are both at the edge of a 9.0 meter wide track, how much further back should Ted start his turn than Bill?

Hint #1 - the track width is one of the sides of a 90 degree triangle.

Hint #2 - the "start point" of the turn to the "apex" is a straight line and forms the hypotenuse.

Enjoy.

RamblinRover Luxury-Yacht > themanwithsauce - has as many vehicles as job titles 01/21/2014 at 09:29

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Sounds like way above his current level and not an identity question per se, but I'll allow it because "Whoa".

themanwithsauce - has as many vehicles as job titles > RamblinRover Luxury-Yacht 01/21/2014 at 09:35

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Excellent!

And yeah it's a challenge mode question. Aim high.

RMudkips > themanwithsauce - has as many vehicles as job titles 01/21/2014 at 10:10

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I'm probably inclined to solve this. Thanks

RMudkips > themanwithsauce - has as many vehicles as job titles 01/21/2014 at 10:20

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Here's a diagram I drew of it.

themanwithsauce - has as many vehicles as job titles > RMudkips 01/21/2014 at 10:29

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The diagram looks correct for what I was thinking. I think the math is about 1.75 meters difference between them. Both triangles have an adjacent side of 9.0m so you know the angles and a side to both triangles. Just a matter of setting up the right function to solve the problem.

I should do another one for wayne and garth :P

And I feel like the names are lost on you if you're in a trig course......I'm old :(

RMudkips > themanwithsauce - has as many vehicles as job titles 01/21/2014 at 10:36

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Got a different answer.

I kmow who they are, just havent seen the movie. The course is functions; haven't done trig like this in a bit.

themanwithsauce - has as many vehicles as job titles > RMudkips 01/21/2014 at 10:43

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tan(x) = (opp/adj)

tan(40) = (9.0/adj)

.839 = 9.0/adj

(0.893)*adj = 9.0

adj = 9.0/0.893 = 10.75. So Ted must start 10.75m back

tan(45) = 9.0/adj = 1.0

so adj = 9.0m since the tan of 45 is 1.

10.75-9.0 = 1.75

RMudkips > themanwithsauce - has as many vehicles as job titles 01/21/2014 at 10:53

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Wait, wouldn't the opposite be 9^2 + x^2, since hyp is 9?

themanwithsauce - has as many vehicles as job titles > RMudkips 01/21/2014 at 10:55

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The hypotenuse is not nine, the opposite side is. In my head, when I say track width, I pictured it being 9.0m on the adjacent. the path each car follows is the hypotenuse. WHat you're measuring is the difference in start points to the apex (where their hypotenuse path meets the edge of the 9.0m wide track)

RMudkips > themanwithsauce - has as many vehicles as job titles 01/21/2014 at 11:05

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Oh, I see. I'll try this again today. So I didn't really have to use sine law for this. Thanks.